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  1. #121
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    That would be great, please post it; the more data to test the better. People are using MPC to create JCV right?

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  3. #122
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    Ok, here it is: [Only registered and activated users can see links. ].

    Afaik, MPC is the only way to create JCV files, but i think it's limited to Raster files only. Probably best to ask in [Only registered and activated users can see links. ] for more info.
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  4. #123
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    Quote Originally Posted by Neil View Post
    ... but i think it's limited to Raster files only.
    See [Only registered and activated users can see links. ]

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    Anyone got any luck getting this working for NA 3597?

    Thanks in advance!

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    Sorry, no it can't work because of the 3597 firmware being unable to process the specific type of file format used for Asian JCVs. See Post #29 for explanation.
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  7. #126
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    Quote Originally Posted by syzygy View Post
    In the original JCV file there is a pointer at each junction view pointing to the single copyright warning picture. All the patch tool does is to replace that pointer with another one pointing to the actual junction view picture. Since the patched JCV file works in 2xx5 it proves that the patched pointer is correct and won't cause a crash.
    Interesting kludge from maker of JCV to use top layer of copyright bitmap to hide correct bitmaps. I wonder what kind of mod the firmware have to do to show it correctly. Does it just ignore the last half of the "bit stream?" Or something simpler, stop after displaying the first day and night layer.
    Does the tool just blindly replacing the last two "bit chunks" with the first two?
    Code:
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    Note that jcv2Offset=0x992f is the copyright bitmap.

    If so, what if JCV only have day and not night, so a total of two "bit chunks", one for correct day and one for copyright. Do you then just replaced the last one with same value as first?
    Last edited by osiris4isis; 22nd August 2015 at 07:46.

  8. #127
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    Quote Originally Posted by osiris4isis View Post
    Does the tool just blindly replacing the last two "bit chunks" with the first two?

    If so, what if JCV only have day and not night, so a total of two "bit chunks", one for correct day and one for copyright. Do you then just replaced the last one with same value as first?
    In general, there are two lists of equal number of JCV2 offsets. Each member of the first list points to a real picture. While each member of the second list always points to the copyright picture. The last member of a list has the end-of-list bit set to 1. The tool simply copies the JCV2 offsets from the first list to the second list.

    In your example, there are two members in each list, one for day and one for night. But the same algorithm will work for just one member or N members per list.

  9. #128
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    Quote Originally Posted by syzygy View Post
    In general, there are two lists of equal number of JCV2 offsets. Each member of the first list points to a real picture. While each member of the second list always points to the copyright picture. The last member of a list has the end-of-list bit set to 1. The tool simply copies the JCV2 offsets from the first list to the second list.

    In your example, there are two members in each list, one for day and one for night. But the same algorithm will work for just one member or N members per list.
    Thanks syzygy, where is "end-of-list bit" located?

  10. #129
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    Quote Originally Posted by osiris4isis View Post
    Thanks syzygy, where is "end-of-list bit" located?
    It is the 8th bit (i.e. bit 7 of the next byte) after the JCV2 offset.

    In your example, shift bitStream2 to the right by 1 bit then partition the remaining bitstream from right every 24 bits and 8 bits alternatively as below.

    in binary
    1000-0000 0000-0000-1001-1001-0010-1111 0000-0001 0000-0000-1001-1001-0010-1111 1000-0000 0000-0110-0101-1000-1101-1101 0000-0001 0000-0110-0000-0110-0011-0100

    in hex
    80 00992f 01 00992f 80 0658dd 01 060634

  11. #130
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    Quote Originally Posted by syzygy View Post
    It is the 8th bit (i.e. bit 7 of the next byte) after the JCV2 offset.

    In your example, shift bitStream2 to the right by 1 bit then partition the remaining bitstream from right every 24 bits and 8 bits alternatively as below.

    in binary
    1000-0000 0000-0000-1001-1001-0010-1111 0000-0001 0000-0000-1001-1001-0010-1111 1000-0000 0000-0110-0101-1000-1101-1101 0000-0001 0000-0110-0000-0110-0011-0100

    in hex
    80 00992f 01 00992f 80 0658dd 01 060634
    So the XX byte that follows each JCV2 offset are:
    Code:
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    Does this means bit1 is for day/night (day=1 and night=0)? If so, any idea of what the 6 middle bits are for?
    Last edited by osiris4isis; 24th August 2015 at 05:57.

 

 
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